2(5z-4)-10=2(z+3)+8

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Solution for 2(5z-4)-10=2(z+3)+8 equation: 



2(5z-4)-10=2(z+3)+8

We move all terms to the left:

2(5z-4)-10-(2(z+3)+8)=0

We multiply parentheses

10z-(2(z+3)+8)-8-10=0



We calculate terms in parentheses: -(2(z+3)+8), so:

2(z+3)+8

We multiply parentheses

2z+6+8

We add all the numbers together, and all the variables

2z+14

Back to the equation:

-(2z+14)



We add all the numbers together, and all the variables

10z-(2z+14)-18=0

We get rid of parentheses

10z-2z-14-18=0

We add all the numbers together, and all the variables

8z-32=0

We move all terms containing z to the left, all other terms to the right

8z=32

z=32/8

z=4

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