2(6+1)=6(b-2)

Solution for 2(6+1)=6(b-2) equation:

2(6+1)=6(b-2)

We move all terms to the left:

2(6+1)-(6(b-2))=0

We add all the numbers together, and all the variables

-(6(b-2))+27=0


We calculate terms in parentheses: -(6(b-2)), so:

6(b-2)

We multiply parentheses

6b-12

Back to the equation:

-(6b-12)


We get rid of parentheses

-6b+12+27=0

We add all the numbers together, and all the variables

-6b+39=0

We move all terms containing b to the left, all other terms to the right

-6b=-39

b=-39/-6

b=6+1/2