2(6+4/5b)=(9/10b)2

Solution for 2(6+4/5b)=(9/10b)2 equation:

2(6+4/5b)=(9/10b)2

We move all terms to the left:

2(6+4/5b)-((9/10b)2)=0


Domain of the equation: 5b)!=0

b!=0/1

b!=0

b∈R



Domain of the equation: 10b)2)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

2(4/5b+6)-((+9/10b)2)=0

We multiply parentheses

8b-((+9/10b)2)+12=0

We multiply all the terms by the denominator


8b*10b)2)-((+12*10b)2)+9=0

Wy multiply elements

80b^2+120b=0

a = 80; b = 120; c = 0;
Δ = b2-4ac
Δ = 1202-4·80·0
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-120}{2*80}=\frac{-240}{160}
=-1+1/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+120}{2*80}=\frac{0}{160}
=0
$