2(6+v)=32

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Solution for 2(6+v)=32 equation: 



2(6+v)=32

We move all terms to the left:

2(6+v)-(32)=0

We add all the numbers together, and all the variables

2(v+6)-32=0

We multiply parentheses

2v+12-32=0

We add all the numbers together, and all the variables

2v-20=0

We move all terms containing v to the left, all other terms to the right

2v=20

v=20/2

v=10

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