2(6-2m)+4m=4(m-1)

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Solution for 2(6-2m)+4m=4(m-1) equation: 



2(6-2m)+4m=4(m-1)

We move all terms to the left:

2(6-2m)+4m-(4(m-1))=0

We add all the numbers together, and all the variables

2(-2m+6)+4m-(4(m-1))=0

We add all the numbers together, and all the variables

4m+2(-2m+6)-(4(m-1))=0

We multiply parentheses

4m-4m-(4(m-1))+12=0



We calculate terms in parentheses: -(4(m-1)), so:

4(m-1)

We multiply parentheses

4m-4

Back to the equation:

-(4m-4)



We add all the numbers together, and all the variables

-(4m-4)+12=0

We get rid of parentheses

-4m+4+12=0

We add all the numbers together, and all the variables

-4m+16=0

We move all terms containing m to the left, all other terms to the right

-4m=-16

m=-16/-4

m=+4

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