2(6-2z)-4(2z+9)=z-28

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Solution for 2(6-2z)-4(2z+9)=z-28 equation: 



2(6-2z)-4(2z+9)=z-28

We move all terms to the left:

2(6-2z)-4(2z+9)-(z-28)=0

We add all the numbers together, and all the variables

2(-2z+6)-4(2z+9)-(z-28)=0

We multiply parentheses

-4z-8z-(z-28)+12-36=0

We get rid of parentheses

-4z-8z-z+28+12-36=0

We add all the numbers together, and all the variables

-13z+4=0

We move all terms containing z to the left, all other terms to the right

-13z=-4

z=-4/-13

z=4/13

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