2(6-3b)=-2b+32

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Solution for 2(6-3b)=-2b+32 equation: 



2(6-3b)=-2b+32

We move all terms to the left:

2(6-3b)-(-2b+32)=0

We add all the numbers together, and all the variables

2(-3b+6)-(-2b+32)=0

We multiply parentheses

-6b-(-2b+32)+12=0

We get rid of parentheses

-6b+2b-32+12=0

We add all the numbers together, and all the variables

-4b-20=0

We move all terms containing b to the left, all other terms to the right

-4b=20

b=20/-4

b=-5

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