2(6-3x)=(1+2x)/3

Solution for 2(6-3x)=(1+2x)/3 equation:

2(6-3x)=(1+2x)/3

We move all terms to the left:

2(6-3x)-((1+2x)/3)=0

We add all the numbers together, and all the variables

2(-3x+6)-((2x+1)/3)=0

We multiply parentheses

-6x-((2x+1)/3)+12=0

We multiply all the terms by the denominator


-6x*3)-((2x+1)+12*3)=0

We add all the numbers together, and all the variables

-6x*3)-((2x+1)=0

Wy multiply elements

-18x^2=0

a = -18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-18)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-36}=0$