2(6-u)/3=2u+6

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Solution for 2(6-u)/3=2u+6 equation: 



2(6-u)/3=2u+6

We move all terms to the left:

2(6-u)/3-(2u+6)=0

We add all the numbers together, and all the variables

2(-1u+6)/3-(2u+6)=0

We get rid of parentheses

2(-1u+6)/3-2u-6=0

We multiply all the terms by the denominator


2(-1u+6)-2u*3-6*3=0

We add all the numbers together, and all the variables

2(-1u+6)-2u*3-18=0

We multiply parentheses

-2u-2u*3+12-18=0

Wy multiply elements

-2u-6u+12-18=0

We add all the numbers together, and all the variables

-8u-6=0

We move all terms containing u to the left, all other terms to the right

-8u=6

u=6/-8

u=-3/4

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