2(6-u)=9(u+5)

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Solution for 2(6-u)=9(u+5) equation: 



2(6-u)=9(u+5)

We move all terms to the left:

2(6-u)-(9(u+5))=0

We add all the numbers together, and all the variables

2(-1u+6)-(9(u+5))=0

We multiply parentheses

-2u-(9(u+5))+12=0



We calculate terms in parentheses: -(9(u+5)), so:

9(u+5)

We multiply parentheses

9u+45

Back to the equation:

-(9u+45)



We get rid of parentheses

-2u-9u-45+12=0

We add all the numbers together, and all the variables

-11u-33=0

We move all terms containing u to the left, all other terms to the right

-11u=33

u=33/-11

u=-3

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