2(6-x)+4=(x-3/2)-2

Solution for 2(6-x)+4=(x-3/2)-2 equation:

2(6-x)+4=(x-3/2)-2

We move all terms to the left:

2(6-x)+4-((x-3/2)-2)=0

We add all the numbers together, and all the variables

2(-1x+6)-((+x-3/2)-2)+4=0

We multiply parentheses

-2x-((+x-3/2)-2)+12+4=0

We multiply all the terms by the denominator


-2x*2)-2)-((+x-3+12*2)-2)+4*2)-2)=0

We add all the numbers together, and all the variables

-2x*2)-2)-((x+21)-2)+4*2)-2)=0

We add all the numbers together, and all the variables

-2x*2)-2)-((x=0

Wy multiply elements

-4x^2=0

a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-8}=0$