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2(6-x)=3(x+1)
We move all terms to the left:
2(6-x)-(3(x+1))=0
We add all the numbers together, and all the variables
2(-1x+6)-(3(x+1))=0
We multiply parentheses
-2x-(3(x+1))+12=0
We calculate terms in parentheses: -(3(x+1)), so:We get rid of parentheses
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
-2x-3x-3+12=0
We add all the numbers together, and all the variables
-5x+9=0
We move all terms containing x to the left, all other terms to the right
-5x=-9
x=-9/-5
x=1+4/5
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