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2(6-x)=3(x-1)
We move all terms to the left:
2(6-x)-(3(x-1))=0
We add all the numbers together, and all the variables
2(-1x+6)-(3(x-1))=0
We multiply parentheses
-2x-(3(x-1))+12=0
We calculate terms in parentheses: -(3(x-1)), so:We get rid of parentheses
3(x-1)
We multiply parentheses
3x-3
Back to the equation:
-(3x-3)
-2x-3x+3+12=0
We add all the numbers together, and all the variables
-5x+15=0
We move all terms containing x to the left, all other terms to the right
-5x=-15
x=-15/-5
x=+3
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