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2(6/n)=3(n+9)
We move all terms to the left:
2(6/n)-(3(n+9))=0
Domain of the equation: n)!=0We add all the numbers together, and all the variables
n!=0/1
n!=0
n∈R
2(+6/n)-(3(n+9))=0
We multiply parentheses
12n-(3(n+9))=0
We calculate terms in parentheses: -(3(n+9)), so:We get rid of parentheses
3(n+9)
We multiply parentheses
3n+27
Back to the equation:
-(3n+27)
12n-3n-27=0
We add all the numbers together, and all the variables
9n-27=0
We move all terms containing n to the left, all other terms to the right
9n=27
n=27/9
n=3
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