2(63-22x)=x-36

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Solution for 2(63-22x)=x-36 equation: 



2(63-22x)=x-36

We move all terms to the left:

2(63-22x)-(x-36)=0

We add all the numbers together, and all the variables

2(-22x+63)-(x-36)=0

We multiply parentheses

-44x-(x-36)+126=0

We get rid of parentheses

-44x-x+36+126=0

We add all the numbers together, and all the variables

-45x+162=0

We move all terms containing x to the left, all other terms to the right

-45x=-162

x=-162/-45

x=3+3/5

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