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2(6a+4)(2a+3)=0
We multiply parentheses ..
2(+12a^2+18a+8a+12)=0
We multiply parentheses
24a^2+36a+16a+24=0
We add all the numbers together, and all the variables
24a^2+52a+24=0
a = 24; b = 52; c = +24;
Δ = b2-4ac
Δ = 522-4·24·24
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-20}{2*24}=\frac{-72}{48} =-1+1/2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+20}{2*24}=\frac{-32}{48} =-2/3 $
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