2(6b+1)=4(b-5)-3

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Solution for 2(6b+1)=4(b-5)-3 equation: 



2(6b+1)=4(b-5)-3

We move all terms to the left:

2(6b+1)-(4(b-5)-3)=0

We multiply parentheses

12b-(4(b-5)-3)+2=0



We calculate terms in parentheses: -(4(b-5)-3), so:

4(b-5)-3

We multiply parentheses

4b-20-3

We add all the numbers together, and all the variables

4b-23

Back to the equation:

-(4b-23)



We get rid of parentheses

12b-4b+23+2=0

We add all the numbers together, and all the variables

8b+25=0

We move all terms containing b to the left, all other terms to the right

8b=-25

b=-25/8

b=-3+1/8

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