2(6b+2)=13+3b

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Solution for 2(6b+2)=13+3b equation: 



2(6b+2)=13+3b

We move all terms to the left:

2(6b+2)-(13+3b)=0

We add all the numbers together, and all the variables

2(6b+2)-(3b+13)=0

We multiply parentheses

12b-(3b+13)+4=0

We get rid of parentheses

12b-3b-13+4=0

We add all the numbers together, and all the variables

9b-9=0

We move all terms containing b to the left, all other terms to the right

9b=9

b=9/9

b=1

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