2(6b-1)=4(b-5)-2

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Solution for 2(6b-1)=4(b-5)-2 equation: 



2(6b-1)=4(b-5)-2

We move all terms to the left:

2(6b-1)-(4(b-5)-2)=0

We multiply parentheses

12b-(4(b-5)-2)-2=0



We calculate terms in parentheses: -(4(b-5)-2), so:

4(b-5)-2

We multiply parentheses

4b-20-2

We add all the numbers together, and all the variables

4b-22

Back to the equation:

-(4b-22)



We get rid of parentheses

12b-4b+22-2=0

We add all the numbers together, and all the variables

8b+20=0

We move all terms containing b to the left, all other terms to the right

8b=-20

b=-20/8

b=-2+1/2

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