2(6b-20)-6=2(2b+13)+16

Solution for 2(6b-20)-6=2(2b+13)+16 equation:

2(6b-20)-6=2(2b+13)+16

We move all terms to the left:

2(6b-20)-6-(2(2b+13)+16)=0

We multiply parentheses

12b-(2(2b+13)+16)-40-6=0


We calculate terms in parentheses: -(2(2b+13)+16), so:

2(2b+13)+16

We multiply parentheses

4b+26+16

We add all the numbers together, and all the variables

4b+42

Back to the equation:

-(4b+42)


We add all the numbers together, and all the variables

12b-(4b+42)-46=0

We get rid of parentheses

12b-4b-42-46=0

We add all the numbers together, and all the variables

8b-88=0

We move all terms containing b to the left, all other terms to the right

8b=88

b=88/8

b=11