2(6c+1)-15=9c+5

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Solution for 2(6c+1)-15=9c+5 equation:



2(6c+1)-15=9c+5
We move all terms to the left:
2(6c+1)-15-(9c+5)=0
We multiply parentheses
12c-(9c+5)+2-15=0
We get rid of parentheses
12c-9c-5+2-15=0
We add all the numbers together, and all the variables
3c-18=0
We move all terms containing c to the left, all other terms to the right
3c=18
c=18/3
c=6

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