2(6j-12)=6(j+4)

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Solution for 2(6j-12)=6(j+4) equation: 



2(6j-12)=6(j+4)

We move all terms to the left:

2(6j-12)-(6(j+4))=0

We multiply parentheses

12j-(6(j+4))-24=0



We calculate terms in parentheses: -(6(j+4)), so:

6(j+4)

We multiply parentheses

6j+24

Back to the equation:

-(6j+24)



We get rid of parentheses

12j-6j-24-24=0

We add all the numbers together, and all the variables

6j-48=0

We move all terms containing j to the left, all other terms to the right

6j=48

j=48/6

j=8

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