2(6m+8)=(10-m)

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Solution for 2(6m+8)=(10-m) equation: 



2(6m+8)=(10-m)

We move all terms to the left:

2(6m+8)-((10-m))=0

We add all the numbers together, and all the variables

2(6m+8)-((-1m+10))=0

We multiply parentheses

12m-((-1m+10))+16=0



We calculate terms in parentheses: -((-1m+10)), so:

(-1m+10)

We get rid of parentheses

-1m+10

Back to the equation:

-(-1m+10)



We get rid of parentheses

12m+1m-10+16=0

We add all the numbers together, and all the variables

13m+6=0

We move all terms containing m to the left, all other terms to the right

13m=-6

m=-6/13

m=-6/13

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