2(6n+2)+4n=6(4n-6)+22n

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Solution for 2(6n+2)+4n=6(4n-6)+22n equation: 



2(6n+2)+4n=6(4n-6)+22n

We move all terms to the left:

2(6n+2)+4n-(6(4n-6)+22n)=0

We add all the numbers together, and all the variables

4n+2(6n+2)-(6(4n-6)+22n)=0

We multiply parentheses

4n+12n-(6(4n-6)+22n)+4=0



We calculate terms in parentheses: -(6(4n-6)+22n), so:

6(4n-6)+22n

We add all the numbers together, and all the variables

22n+6(4n-6)

We multiply parentheses

22n+24n-36

We add all the numbers together, and all the variables

46n-36

Back to the equation:

-(46n-36)



We add all the numbers together, and all the variables

16n-(46n-36)+4=0

We get rid of parentheses

16n-46n+36+4=0

We add all the numbers together, and all the variables

-30n+40=0

We move all terms containing n to the left, all other terms to the right

-30n=-40

n=-40/-30

n=1+1/3

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