2(6r-4)+2(3-2r)=38

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Solution for 2(6r-4)+2(3-2r)=38 equation: 



2(6r-4)+2(3-2r)=38

We move all terms to the left:

2(6r-4)+2(3-2r)-(38)=0

We add all the numbers together, and all the variables

2(6r-4)+2(-2r+3)-38=0

We multiply parentheses

12r-4r-8+6-38=0

We add all the numbers together, and all the variables

8r-40=0

We move all terms containing r to the left, all other terms to the right

8r=40

r=40/8

r=5

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