2(6r-5)+4r=-2(1-2r)-8

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Solution for 2(6r-5)+4r=-2(1-2r)-8 equation: 



2(6r-5)+4r=-2(1-2r)-8

We move all terms to the left:

2(6r-5)+4r-(-2(1-2r)-8)=0

We add all the numbers together, and all the variables

2(6r-5)+4r-(-2(-2r+1)-8)=0

We add all the numbers together, and all the variables

4r+2(6r-5)-(-2(-2r+1)-8)=0

We multiply parentheses

4r+12r-(-2(-2r+1)-8)-10=0



We calculate terms in parentheses: -(-2(-2r+1)-8), so:

-2(-2r+1)-8

We multiply parentheses

4r-2-8

We add all the numbers together, and all the variables

4r-10

Back to the equation:

-(4r-10)



We add all the numbers together, and all the variables

16r-(4r-10)-10=0

We get rid of parentheses

16r-4r+10-10=0

We add all the numbers together, and all the variables

12r=0

r=0/12

r=0

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