2(6t+1)-13=t(t+10)

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Solution for 2(6t+1)-13=t(t+10) equation: 



2(6t+1)-13=t(t+10)

We move all terms to the left:

2(6t+1)-13-(t(t+10))=0

We multiply parentheses

12t-(t(t+10))+2-13=0



We calculate terms in parentheses: -(t(t+10)), so:

t(t+10)

We multiply parentheses

t^2+10t

Back to the equation:

-(t^2+10t)



We add all the numbers together, and all the variables

12t-(t^2+10t)-11=0

We get rid of parentheses

-t^2+12t-10t-11=0

We add all the numbers together, and all the variables

-1t^2+2t-11=0

a = -1; b = 2; c = -11;
Δ = b2-4ac
Δ = 22-4·(-1)·(-11)
Δ = -40
Delta is less than zero, so there is no solution for the equation

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