2(6t+1)-4(t+1)=0

Solution for 2(6t+1)-4(t+1)=0 equation:

Simplifying
2(6t + 1) + -4(t + 1) = 0

Reorder the terms:
2(1 + 6t) + -4(t + 1) = 0
(1 * 2 + 6t * 2) + -4(t + 1) = 0
(2 + 12t) + -4(t + 1) = 0

Reorder the terms:
2 + 12t + -4(1 + t) = 0
2 + 12t + (1 * -4 + t * -4) = 0
2 + 12t + (-4 + -4t) = 0

Reorder the terms:
2 + -4 + 12t + -4t = 0

Combine like terms: 2 + -4 = -2
-2 + 12t + -4t = 0

Combine like terms: 12t + -4t = 8t
-2 + 8t = 0

Solving
-2 + 8t = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 8t = 0 + 2

Combine like terms: -2 + 2 = 0
0 + 8t = 0 + 2
8t = 0 + 2

Combine like terms: 0 + 2 = 2
8t = 2

Divide each side by '8'.
t = 0.25

Simplifying
t = 0.25