2(6u-6)-18=4(u+5)+6

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Solution for 2(6u-6)-18=4(u+5)+6 equation: 



2(6u-6)-18=4(u+5)+6

We move all terms to the left:

2(6u-6)-18-(4(u+5)+6)=0

We multiply parentheses

12u-(4(u+5)+6)-12-18=0



We calculate terms in parentheses: -(4(u+5)+6), so:

4(u+5)+6

We multiply parentheses

4u+20+6

We add all the numbers together, and all the variables

4u+26

Back to the equation:

-(4u+26)



We add all the numbers together, and all the variables

12u-(4u+26)-30=0

We get rid of parentheses

12u-4u-26-30=0

We add all the numbers together, and all the variables

8u-56=0

We move all terms containing u to the left, all other terms to the right

8u=56

u=56/8

u=7

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