2(6x+1)-3x=10-(x-2)

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Solution for 2(6x+1)-3x=10-(x-2) equation: 



2(6x+1)-3x=10-(x-2)

We move all terms to the left:

2(6x+1)-3x-(10-(x-2))=0

We add all the numbers together, and all the variables

-3x+2(6x+1)-(10-(x-2))=0

We multiply parentheses

-3x+12x-(10-(x-2))+2=0



We calculate terms in parentheses: -(10-(x-2)), so:

10-(x-2)

determiningTheFunctionDomain
-(x-2)+10

We get rid of parentheses

-x+2+10

We add all the numbers together, and all the variables

-1x+12

Back to the equation:

-(-1x+12)



We add all the numbers together, and all the variables

9x-(-1x+12)+2=0

We get rid of parentheses

9x+1x-12+2=0

We add all the numbers together, and all the variables

10x-10=0

We move all terms containing x to the left, all other terms to the right

10x=10

x=10/10

x=1

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