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2(6x+1)=2(4+5/2x)
We move all terms to the left:
2(6x+1)-(2(4+5/2x))=0
Domain of the equation: 2x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2(6x+1)-(2(5/2x+4))=0
We multiply parentheses
12x-(2(5/2x+4))+2=0
We multiply all the terms by the denominator
12x*2x+2*2x+4))-(2(5+4))=0
We add all the numbers together, and all the variables
12x*2x+2*2x+4))-(29)=0
We add all the numbers together, and all the variables
12x*2x+2*2x=0
Wy multiply elements
24x^2+4x=0
a = 24; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·24·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*24}=\frac{-8}{48} =-1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*24}=\frac{0}{48} =0 $
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