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2(6x+1)=2(x-5)-18
We move all terms to the left:
2(6x+1)-(2(x-5)-18)=0
We multiply parentheses
12x-(2(x-5)-18)+2=0
We calculate terms in parentheses: -(2(x-5)-18), so:We get rid of parentheses
2(x-5)-18
We multiply parentheses
2x-10-18
We add all the numbers together, and all the variables
2x-28
Back to the equation:
-(2x-28)
12x-2x+28+2=0
We add all the numbers together, and all the variables
10x+30=0
We move all terms containing x to the left, all other terms to the right
10x=-30
x=-30/10
x=-3
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