2(6x+10)=128

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Solution for 2(6x+10)=128 equation: 



2(6x+10)=128

We move all terms to the left:

2(6x+10)-(128)=0

We multiply parentheses

12x+20-128=0

We add all the numbers together, and all the variables

12x-108=0

We move all terms containing x to the left, all other terms to the right

12x=108

x=108/12

x=9

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