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2(6x+4)-6+x=3(4x+3)+1
We move all terms to the left:
2(6x+4)-6+x-(3(4x+3)+1)=0
We add all the numbers together, and all the variables
x+2(6x+4)-(3(4x+3)+1)-6=0
We multiply parentheses
x+12x-(3(4x+3)+1)+8-6=0
We calculate terms in parentheses: -(3(4x+3)+1), so:We add all the numbers together, and all the variables
3(4x+3)+1
We multiply parentheses
12x+9+1
We add all the numbers together, and all the variables
12x+10
Back to the equation:
-(12x+10)
13x-(12x+10)+2=0
We get rid of parentheses
13x-12x-10+2=0
We add all the numbers together, and all the variables
x-8=0
We move all terms containing x to the left, all other terms to the right
x=8
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