2(6x+5)+3(4x-5)+2-3x+3x-6-5x+4(x-5)=-12-18

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Solution for 2(6x+5)+3(4x-5)+2-3x+3x-6-5x+4(x-5)=-12-18 equation:



2(6x+5)+3(4x-5)+2-3x+3x-6-5x+4(x-5)=-12-18
We move all terms to the left:
2(6x+5)+3(4x-5)+2-3x+3x-6-5x+4(x-5)-(-12-18)=0
We add all the numbers together, and all the variables
2(6x+5)+3(4x-5)-3x+3x-5x+4(x-5)+2-6-(-30)=0
We add all the numbers together, and all the variables
-5x+2(6x+5)+3(4x-5)+4(x-5)+26=0
We multiply parentheses
-5x+12x+12x+4x+10-15-20+26=0
We add all the numbers together, and all the variables
23x+1=0
We move all terms containing x to the left, all other terms to the right
23x=-1
x=-1/23
x=-1/23

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