2(6x-19)=3x+10

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Solution for 2(6x-19)=3x+10 equation: 



2(6x-19)=3x+10

We move all terms to the left:

2(6x-19)-(3x+10)=0

We multiply parentheses

12x-(3x+10)-38=0

We get rid of parentheses

12x-3x-10-38=0

We add all the numbers together, and all the variables

9x-48=0

We move all terms containing x to the left, all other terms to the right

9x=48

x=48/9

x=5+1/3

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