2(6x-3)=4(2+4x)

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Solution for 2(6x-3)=4(2+4x) equation: 



2(6x-3)=4(2+4x)

We move all terms to the left:

2(6x-3)-(4(2+4x))=0

We add all the numbers together, and all the variables

2(6x-3)-(4(4x+2))=0

We multiply parentheses

12x-(4(4x+2))-6=0



We calculate terms in parentheses: -(4(4x+2)), so:

4(4x+2)

We multiply parentheses

16x+8

Back to the equation:

-(16x+8)



We get rid of parentheses

12x-16x-8-6=0

We add all the numbers together, and all the variables

-4x-14=0

We move all terms containing x to the left, all other terms to the right

-4x=14

x=14/-4

x=-3+1/2

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