2(6x-4)=3(4x-3)+1

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Solution for 2(6x-4)=3(4x-3)+1 equation: 



2(6x-4)=3(4x-3)+1

We move all terms to the left:

2(6x-4)-(3(4x-3)+1)=0

We multiply parentheses

12x-(3(4x-3)+1)-8=0



We calculate terms in parentheses: -(3(4x-3)+1), so:

3(4x-3)+1

We multiply parentheses

12x-9+1

We add all the numbers together, and all the variables

12x-8

Back to the equation:

-(12x-8)



We get rid of parentheses

12x-12x+8-8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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