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2(6x-4)=3(x-2)
We move all terms to the left:
2(6x-4)-(3(x-2))=0
We multiply parentheses
12x-(3(x-2))-8=0
We calculate terms in parentheses: -(3(x-2)), so:We get rid of parentheses
3(x-2)
We multiply parentheses
3x-6
Back to the equation:
-(3x-6)
12x-3x+6-8=0
We add all the numbers together, and all the variables
9x-2=0
We move all terms containing x to the left, all other terms to the right
9x=2
x=2/9
x=2/9
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