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2(6x-5)=(5x+1)+2x
We move all terms to the left:
2(6x-5)-((5x+1)+2x)=0
We multiply parentheses
12x-((5x+1)+2x)-10=0
We calculate terms in parentheses: -((5x+1)+2x), so:We get rid of parentheses
(5x+1)+2x
We add all the numbers together, and all the variables
2x+(5x+1)
We get rid of parentheses
2x+5x+1
We add all the numbers together, and all the variables
7x+1
Back to the equation:
-(7x+1)
12x-7x-1-10=0
We add all the numbers together, and all the variables
5x-11=0
We move all terms containing x to the left, all other terms to the right
5x=11
x=11/5
x=2+1/5
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