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2(6x-5)=-(3x+1)*6
We move all terms to the left:
2(6x-5)-(-(3x+1)*6)=0
We multiply parentheses
12x-(-(3x+1)*6)-10=0
We calculate terms in parentheses: -(-(3x+1)*6), so:We get rid of parentheses
-(3x+1)*6
We multiply parentheses
-18x-6
Back to the equation:
-(-18x-6)
12x+18x+6-10=0
We add all the numbers together, and all the variables
30x-4=0
We move all terms containing x to the left, all other terms to the right
30x=4
x=4/30
x=2/15
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