2(6x-5)=-3(x+1)

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Solution for 2(6x-5)=-3(x+1) equation: 



2(6x-5)=-3(x+1)

We move all terms to the left:

2(6x-5)-(-3(x+1))=0

We multiply parentheses

12x-(-3(x+1))-10=0



We calculate terms in parentheses: -(-3(x+1)), so:

-3(x+1)

We multiply parentheses

-3x-3

Back to the equation:

-(-3x-3)



We get rid of parentheses

12x+3x+3-10=0

We add all the numbers together, and all the variables

15x-7=0

We move all terms containing x to the left, all other terms to the right

15x=7

x=7/15

x=7/15

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