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2(6x-5)=2(5x+1)+2x
We move all terms to the left:
2(6x-5)-(2(5x+1)+2x)=0
We multiply parentheses
12x-(2(5x+1)+2x)-10=0
We calculate terms in parentheses: -(2(5x+1)+2x), so:We get rid of parentheses
2(5x+1)+2x
We add all the numbers together, and all the variables
2x+2(5x+1)
We multiply parentheses
2x+10x+2
We add all the numbers together, and all the variables
12x+2
Back to the equation:
-(12x+2)
12x-12x-2-10=0
We add all the numbers together, and all the variables
-12!=0
There is no solution for this equation
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