2(6x-5)=27

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Solution for 2(6x-5)=27 equation: 



2(6x-5)=27

We move all terms to the left:

2(6x-5)-(27)=0

We multiply parentheses

12x-10-27=0

We add all the numbers together, and all the variables

12x-37=0

We move all terms containing x to the left, all other terms to the right

12x=37

x=37/12

x=3+1/12

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