2(6x-7)=2x+41

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Solution for 2(6x-7)=2x+41 equation: 



2(6x-7)=2x+41

We move all terms to the left:

2(6x-7)-(2x+41)=0

We multiply parentheses

12x-(2x+41)-14=0

We get rid of parentheses

12x-2x-41-14=0

We add all the numbers together, and all the variables

10x-55=0

We move all terms containing x to the left, all other terms to the right

10x=55

x=55/10

x=5+1/2

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