2(6y+1)+13=51+9(y-5)

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Solution for 2(6y+1)+13=51+9(y-5) equation: 



2(6y+1)+13=51+9(y-5)

We move all terms to the left:

2(6y+1)+13-(51+9(y-5))=0

We multiply parentheses

12y-(51+9(y-5))+2+13=0



We calculate terms in parentheses: -(51+9(y-5)), so:

51+9(y-5)

determiningTheFunctionDomain
9(y-5)+51

We multiply parentheses

9y-45+51

We add all the numbers together, and all the variables

9y+6

Back to the equation:

-(9y+6)



We add all the numbers together, and all the variables

12y-(9y+6)+15=0

We get rid of parentheses

12y-9y-6+15=0

We add all the numbers together, and all the variables

3y+9=0

We move all terms containing y to the left, all other terms to the right

3y=-9

y=-9/3

y=-3

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