2(6y-18)-102=78-18(y-2)

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Solution for 2(6y-18)-102=78-18(y-2) equation: 



2(6y-18)-102=78-18(y-2)

We move all terms to the left:

2(6y-18)-102-(78-18(y-2))=0

We multiply parentheses

12y-(78-18(y-2))-36-102=0



We calculate terms in parentheses: -(78-18(y-2)), so:

78-18(y-2)

determiningTheFunctionDomain
-18(y-2)+78

We multiply parentheses

-18y+36+78

We add all the numbers together, and all the variables

-18y+114

Back to the equation:

-(-18y+114)



We add all the numbers together, and all the variables

12y-(-18y+114)-138=0

We get rid of parentheses

12y+18y-114-138=0

We add all the numbers together, and all the variables

30y-252=0

We move all terms containing y to the left, all other terms to the right

30y=252

y=252/30

y=8+2/5

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