2(6y-4y)+10=8y-10

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Solution for 2(6y-4y)+10=8y-10 equation: 



2(6y-4y)+10=8y-10

We move all terms to the left:

2(6y-4y)+10-(8y-10)=0

We add all the numbers together, and all the variables

2(+2y)-(8y-10)+10=0

We multiply parentheses

4y-(8y-10)+10=0

We get rid of parentheses

4y-8y+10+10=0

We add all the numbers together, and all the variables

-4y+20=0

We move all terms containing y to the left, all other terms to the right

-4y=-20

y=-20/-4

y=+5

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