2(6y-8)-y=-3(y-4)

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Solution for 2(6y-8)-y=-3(y-4) equation: 



2(6y-8)-y=-3(y-4)

We move all terms to the left:

2(6y-8)-y-(-3(y-4))=0

We add all the numbers together, and all the variables

-1y+2(6y-8)-(-3(y-4))=0

We multiply parentheses

-1y+12y-(-3(y-4))-16=0



We calculate terms in parentheses: -(-3(y-4)), so:

-3(y-4)

We multiply parentheses

-3y+12

Back to the equation:

-(-3y+12)



We add all the numbers together, and all the variables

11y-(-3y+12)-16=0

We get rid of parentheses

11y+3y-12-16=0

We add all the numbers together, and all the variables

14y-28=0

We move all terms containing y to the left, all other terms to the right

14y=28

y=28/14

y=2

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