2(6z+)=28

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Solution for 2(6z+)=28 equation: 



2(6z+)=28

We move all terms to the left:

2(6z+)-(28)=0

We add all the numbers together, and all the variables

2(+6z)-28=0

We multiply parentheses

12z-28=0

We move all terms containing z to the left, all other terms to the right

12z=28

z=28/12

z=2+1/3

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